4-x/x^2+4x-32

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Solution for 4-x/x^2+4x-32 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(x/(x^2))-32+4 = 0

4*x-x^-1-32+4 = 0

4*x^1-1*x^-1-28*x^0 = 0

(4*x^2-28*x^1-1*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-28*x^1-1*x^0) = 0

x^1

4*x^2-28*x-1 = 0

4*x^2-28*x-1 = 0

DELTA = (-28)^2-(-1*4*4)

DELTA = 800

DELTA > 0

x = (800^(1/2)+28)/(2*4) or x = (28-800^(1/2))/(2*4)

x = (20*2^(1/2)+28)/8 or x = (28-20*2^(1/2))/8

x in { (28-20*2^(1/2))/8, (20*2^(1/2)+28)/8} 

x in { (28-20*2^(1/2))/8, (20*2^(1/2)+28)/8 }

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